Testing some geometry routines in C++
[andmenj-acm.git] / 10069 - Distinct subsequences / 10069.cpp
blobe7cf4fe08c4d563d0fd63472e70e1ba44fa9bf37
1 #include <iostream>
3 using namespace std;
6 const int MAX = 200;
8 class HugeInt {
9 public:
11 // vars
12 char number[MAX];
13 int length;
15 // constructors
16 HugeInt() {
17 memset(number,0,sizeof(number));
18 length = 1;
21 HugeInt(int n) {
22 *this = n;
25 // operators
26 // takes 'r' as right number and writes result to 'this'
27 // *veryfied*
28 HugeInt* operator= (const HugeInt* r) {
29 memset(number,0,sizeof(number));
30 strcpy(number,r->number);
31 length = r->length;
32 return this;
35 // *veryfied*
36 HugeInt* operator= (const int r) {
37 memset(number,0,sizeof(number));
38 sprintf(number,"%d",r);
39 length = strlen(number);
40 for (int i = 0; i < (length >> 1); i++) {
41 char c = number[i];
42 number[i] = number[length-i-1];
43 number[length-i-1] = c;
45 for (int j = 0; j < length; j++)
46 number[j] -= '0';
47 return this;
50 // *veryfied*
51 const HugeInt operator+ (const HugeInt& r) {
52 int n = max(length,r.length), carry = 0, k, i;
53 HugeInt theNew;
54 for (i = 0; i < n || carry; i++) {
55 k = number[i] + r.number[i] + carry;
56 theNew.number[i] = k % 10;
57 carry = k / 10;
59 theNew.length = i;
60 return theNew;
63 // slightly veryfied
64 void operator+= (const HugeInt& r) {
65 *this = *this + r;
68 // *slightly veryfied*
69 const HugeInt operator* (const int r) {
70 int i, k, carry = 0;
71 HugeInt theNew;
72 for (i = 0; i < length || carry; i++) {
73 k = number[i] * r + carry;
74 theNew.number[i] = k % 10;
75 carry = k / 10;
77 theNew.length = i;
78 return theNew;
81 // *slightly veryfied*
82 void operator*= (const int r) {
83 *this = *this * r;
84 //return this;
87 // shifts number left by 'shift' positions
88 // useful when multiplying two HugeInt's
89 HugeInt operator<< (const int shift) {
90 int i;
91 HugeInt theNew;
92 // don't shift if number is 0 and there is no number
93 //if (length == 0 || length == 1 && number[0] == 0) return;
94 for (i = length - 1; i >= 0; i--)
95 theNew.number[i + shift] = number[i];
96 for (i = 0; i < shift; i++)
97 theNew.number[i] = 0;
98 theNew.length = length + shift;
99 return theNew;
102 HugeInt operator* (HugeInt& r) {
103 int i;
104 HugeInt theNew = 0;
105 for (i = 0; i < length; i++)
106 theNew += (r << i) * number[i];
107 truncate(theNew);
108 return theNew;
111 HugeInt operator*= (HugeInt& r) {
112 *this = *this * r;
113 return *this;
116 int operator % (int r) {
117 int n = 0;
118 for (int i = length - 1; i >= 0; i--)
119 n = (n * 10 + number[i]) % r;
120 return n;
123 int operator %= (int r) {
124 return (*this % r);
127 HugeInt operator/ (int r) {
128 HugeInt I = 0;
129 int n = 0;
130 int j = 0;
131 for (int i = length - 1; i >= 0 || n >= r; i--) {
132 n = (n * 10 + number[i]);
133 I.number[j++] = n / r;
134 n %= r;
137 // reverse string
138 for (int i = 0; i < j / 2; i++)
139 swap(I.number[i],I.number[j-i-1]);
140 I.length = j;
141 truncate(I);
143 return I;
146 HugeInt operator /= (int r) {
147 return (*this / r);
150 // functions
151 // *veryfied*
152 void print() {
153 for (int i = length - 1; i >= 0; i--)
154 putchar(number[i] + '0');
157 void truncate(HugeInt& n) {
158 for (int i = n.length - 1; i >= 0 && n.number[i] == 0; i--)
159 n.length--;
160 if (n.length == 0) {
161 n.number[0] = 0;
162 n.length = 1;
166 HugeInt power(int p) {
167 HugeInt theNew = 1;
168 for (int i = 0; i < p; i++)
169 theNew *= *this;
170 return theNew;
173 bool operator<(const HugeInt& rhs) {
174 if (this->length != rhs.length)
175 return this->length < rhs.length;
176 for (int i = 0; i < this->length; i++)
177 if (this->number[i] != rhs.number[i])
178 return this->number[i] < rhs.number[i];
179 return false;
182 bool isnull() {
183 if (length == 1 && number[0] == 0) {
184 return true;
186 return false;
192 HugeInt dp[2][10000];
194 dp[i][j] = cantidad de maneras diferentes
195 en que puedo distribuir las primeras i
196 letras de la subsecuencia (b) terminando
197 en la letra j de la secuencia original (a)
200 int main(){
201 int Casos;
202 cin >> Casos;
203 string a, b;
204 getline(cin, a);
205 while (Casos--){
206 getline(cin, a);
207 getline(cin, b);
209 if (b.size() > a.size()){
210 cout << "0" << endl;
211 continue;
214 int A = a.size(), B = b.size();
215 dp[0][0] = int(a[0] == b[0]);
216 for (int j=1; j<A; ++j){
217 dp[0][j] = dp[0][j-1] + int(a[j] == b[0]);
220 for (int i=1; i<B; ++i){
221 dp[i%2][0] = 0;
222 for (int j=1; j<A; ++j){
223 dp[i%2][j] = dp[i%2][j-1];
224 if (a[j] == b[i]){
225 dp[i%2][j] += dp[(i+1)%2][j-1];
229 dp[(B-1)%2][A-1].print();
230 putchar('\n');
233 return 0;